WebAug 7, 2024 · I only want to remove the last one (preferably with that "," as well) – Nick Jones Aug 9, 2024 at 23:40 Ok, if you have 2 carriage returns that you want to replace with a single carriage return you can use this formula. Replace ( {Header.Address},ChrW (10)&ChrW (10), ChrW (10)) – R. McMillan Aug 10, 2024 at 16:45 WebHow to display only the first letter of a string value in a field. Use the Left () function to obtain a certain number of characters from the left end of a text string. For instance, you could use the Left function to obtain just the area code from the values in a …
Crystal Reports remove everything after last occurance of …
WebHow to display the last x characters of a field in Crystal Reports You can use the Right () function to extract a certain number of characters from the end of a field. Answer: Create the formula: Right ( {Field_Name}, #) where # is the number of characters you want to see. WebDec 3, 2024 · Some data has blank space, i am trying to use trim in if condition. if (not isnull(trim({email_id})) then "Email: " + trim({email_id}) else "No Email Entered" blue something anime
Extracting part of a string in Crystal Reports ifonlyidknownthat
WebAug 18, 2008 · I need to remove the space dash space & all text after. Thanks for your help CR85USER & lbass! I wouldnt of figured it out without you. You Rule. This finally worked for me. In case anyone else needs it. left ( {tblCases.To}, instr ( {tblCases.To}," - ")-1) WebOct 19, 2012 · I can do both things but only one at a time. I created a new formula to limit the character number (left ( {Projects.ProjectName},34) and that does the job. I also took the table field and applied a formula in the display string which strips out the unwanted special characters. (Stringvar output := {Projects.ProjectName}; output := Trim (output ... Web3 Answers Sorted by: 18 MID can help here: MID (my_string, 11) // will print your string from character 11 ("D") forward And you can combine MID with INSTR if you need the display to be dynamic (of course this will only work if your data have a consistent format): MID (my_string, (INSTR (my_string, "-") + 2)) Share Improve this answer Follow clear spray on waterproofing